# Solved (Free): Students took two parts of a test, each worth 50 points. Part A has a variance of 25, and Part B has a variance of 49

#### ByDr. Raju Chaudhari

Mar 15, 2021

Students took two parts of a test, each worth 50 points. Part A has a variance of 25, and Part B has a variance of 49. The correlation between the test scores is 0.6.
(a) If the teacher adds the grades of the two parts together to form a final test grade, what would the variance of the final test grades be?
(b) What would the variance of Part A - Part B be?

## Solution

Given that $V(\text{ Part A})= 25$ and $V(\text{Part B})= 49$. Also the correlation between the test scores $r = 0.6$.

 \begin{aligned} Cov(\text{Part A},\text{Part B}) &=r\sqrt{V(\text{Part A})V(\text{Part B})} \\ &=0.6\times \sqrt{25*49}\\ &=21. \end{aligned}

(a) Suppose the teacher adds the grades of the two parts together to form a final test grade.

That is $\text{Final grade} = \text{Grade of Part A} + \text{Grade of Part B}$.

Then the variance of Final grade is

 \begin{aligned} V(\text{Final grade}) &= V(\text{Part A} + \text{Part B})\\ &= V(\text{Part A}) + V(\text{Part B})+ 2 Cov(\text{Part A}, \text{Part B})\\ &= 25 + 49 +2*21\\ &= 116 \end{aligned}

(b) The variance of $\text{Part A} - \text{Part B}$ is

 \begin{aligned} V(\text{Part A} - \text{Part B})&= V(\text{Part A}) + V(\text{Part B})- 2 Cov(\text{Part A}, \text{Part B})\\ &= 25 + 49 -2*21\\ &= 32 \end{aligned}