*** clinical trial *** conducted *** test the *** *** *** *** *** for *** *** *** *** subjects.
After treatment with the *** *** subjects *** a mean *** time *** 95.6 min and *** *** *** 42.1 *** Assume *** the 12 *** *** *** *** be from *** normally distributed *** and
construct *** 90% condence *** *** to the *** deviation *** *** wake times *** *** population
with the *** treatments. Does the *** *** *** the *** is *** that the *** *** *** 12, *** *** deviation iss= *** We *** *** *** *** interval *** *** standard deviation .
Step *** Specify the condence level (1)
Condence level is 1 = *** *** . *** *** level of *** *** = 0 :1 *** 2 Given *** *** sample size n= 12 and sample *** deviation s= 42 *** *** 3 Specify *** formula
100(1 *** condence *** estimate *** *** *** *** is
*** (
n *** 1)s2
2
( *** 2;n *** *** *** *** 1)s2
2
(1 = *** *** *** *** *** 1)and 2
(1 *** 2;n *** *** critical values *** 2distribution *** of *** 1degrees of freedom.
Step *** *** the critical *** *** *** *** 2forlevel *** signicance *** *** freedom *** = 2;n *** 2
(0 *** *** *** and *** *** 2;n *** *** *** *** *** 4
:575 *** *** Determine the *** interval
90 *** condence interval estimate *** population *** *** is
s *** *** *** *** 2;n ***
*** (
n *** *** = 2;n *** *** :41 19
:675
r 11
1772 :41 4
:575
31 :479 *** :
Thus *** *** *** *** *** standard *** *** (31:479 *** :28) .
The *** indicate *** the treatment is eective.
2Critical values *** dist.
04.57519.67523.68
0.050.90.05